ProtocolInequality 运算符

不等于

Definition

命名空间： TouchSocket.Sockets
程序集： TouchSocket (在 TouchSocket.dll 中) 版本：3.0.0+ccaf96084d09f972257496d1dd63b8ba3c1e44f0

C#

public static bool operator !=(
	Protocol a,
	Protocol b
)

VB

Public Shared Operator <> ( 
	a As Protocol,
	b As Protocol
) As Boolean

F#

static let inline (<>)
        a : Protocol * 
        b : Protocol  : bool

a Protocol: [缺少 "M:TouchSocket.Sockets.Protocol.op_Inequality(TouchSocket.Sockets.Protocol,TouchSocket.Sockets.Protocol)" 的 <param name="a"/> 文档]
b Protocol: [缺少 "M:TouchSocket.Sockets.Protocol.op_Inequality(TouchSocket.Sockets.Protocol,TouchSocket.Sockets.Protocol)" 的 <param name="b"/> 文档]

Boolean

[缺少 "M:TouchSocket.Sockets.Protocol.op_Inequality(TouchSocket.Sockets.Protocol,TouchSocket.Sockets.Protocol)" 的 <returns> 文档]